
USER GUIDE SOLID CARBIDE DRILLS General - Calculations Spindle Speed (min-1) Example Drill DR 220-044-25-07-2D-N (Ø22 mm) - Material No. 4 v ∙1000 n= cπ ∙ D kc=2200 N/mm2 k=90º, sin k=1 vc=200 m/min CMh=50 $/h η=0.75 Cutting Speed (m/min) km=1 kf=1 f=0.15 mm/rev L=25 mm h=10 mm π∙D∙n vc ∙ 1000 200 ∙ 1000 vc = 1000 n= π∙D ∙ π ∙ 22 = 2894 min-1 Table Feed (mm/min) vf = f ∙ n=0.15 ∙ 2894 = 434 mm/min vf = f ∙ n vf ∙ π ∙ D2 434 ∙ 3.14 ∙ (22)2 Q= 4000 = 4000 Material Removal Rate (cm3/min) = 165 cm3/min v ∙ π ∙ D2 Q Q= f 4000 Pc = 60.000 ∙ η ∙ Kc ∙ sin k 65 = 60.000 ∙ 0.75 ∙ 2200 ∙ 1 =8.06 kW Power Requirement (kW) Q f ∙ Kc D2 Pc = 60.000 ∙ η ∙ kc ∙ sin k Mc = 10000 ∙ 8 ∙ sin k 0.15 ∙ 2200 222 Torque (Nm) = 10000 ∙ 8 ∙ 1 ∙1 = 20 Nm f∙k D2 D Mc = 1000c ∙ 8 ∙ sin k∙km Ff = 0.63 ∙ 2 ∙f ∙ Kc ∙ sin k 22 = 0.63 ∙ 2 ∙ 0.15 ∙ 2200 ∙ 1 ∙1 = 2286 n Feed Force (approx.) (N) D L+h 25+10 Ff = 0.63 ∙ 2 ∙ f∙kc∙sin k∙kf Tc = Vf = 434 = 0.08 min/piece Machining Time (min/piece) CMh 50 ∙ 0.08 Cc = 60 ∙ Tc = 60 L+h Tc = vf = 0.067 $/piece Machining Cost ($/piece) kc Values Material Material CMh kc Value kc Value Cc = 60 ∙Tc Group Group 1 2000 19 900 2 2100 20 1000 f Feed/rev mm/rev 3 2150 21 500 kc Material specific cutting force N/mm2 4 2200 22 800 Distance from drill point to workpiece 5 2200 23 800 h before feeding mm 6 2100 26 700 L Depth of hole mm 7 2100 27 700 CMh Cost/machine hour $/h 8 2100 28 1700 η Machine efficiency % 9 2100 31 3000 k 90º }180° bottom drills 10 2500 32 3100 sin k 1 DR... 11 3250 33 3300 k 70º }140° point angle drills 12 2300 34 3300 13 2800 35 3200 sin k 0.94 14 2600 36 1700 Drill Geometry Coeficient 15 1100 37 1700 DCM DCN SCD 16 1300 38 4600 km 1 0.85 0.85 17 1100 39 4700 18 1800 40 4600 kf1 0.85 0.85 41 4500 184 ISCAR