General - Calculations

Spindle Speed (min-1) Example

Drill DR 220-044-25-07-2D-N (Ø22 mm) - Material No. 4

n= v ∙1000

c

π ∙ D k =2200 N/mm2k=90º, sin k=1
c
v =200 m/minC=50 $/h η=0.75
cMh
Cutting Speed (m/min)km=1 kf=1f=0.15 mm/revL=25 mm h=10 mm
v = π ∙ D ∙ nn = vc ∙ 1000 ∙ 200 ∙ 1000
c1000π ∙ Dπ ∙ 22 = 2894 min-1
Table Feed (mm/min)v = f ∙ n=0.15 ∙ 2894 = 434 mm/min
f
v = f ∙ n
fvf ∙ π ∙ D
Q =2434 ∙ 3.14 ∙ (22)2
4000=4000
Material Removal Rate (cm3/min)= 165 cm3/min
Q= v ∙ π ∙ D2Q
fP =∙ K ∙ sin k
4000c 60.000 ∙ η c
65
=60.000 ∙ 0.75 ∙ 2200 ∙ 1 =8.06 kW
Power Requirement (kW)
Pc = QM = f ∙ Kc ∙ D2
60.000 ∙ η ∙ kc ∙ sin kc 100008∙ sin k
0.15 ∙ 2200 ∙ 222
Torque (Nm)= 100008∙ 1 ∙1 = 20 Nm
M = f ∙ k ∙ D2D
c c∙ sin k∙km F = 0.63 ∙∙f ∙ K ∙ sin k
10008 f2c
∙ 22
= 0.63 2∙ 0.15 ∙ 2200 ∙ 1 ∙1 = 2286 n
Feed Force (approx.) (N)
F =∙ D ∙T = L+h = 25+10
0.63 f 2f∙kc∙sin k∙kf c= 0.08 min/piece
Vf 434
Machining Time (min/piece)C = CMh50 ∙ 0.08

c 60 ∙ Tc = 60

T = L+h c = 0.067 $/piece vf Machining Cost ($/piece) k Values

c

Material Groupkc ValueMaterial Groupkc Value
1200019900
22100201000
3215021500
4220022800
5220023800
6210026700
7210027700
82100281700
92100313000
102500323100
113250333300
122300343300
132800353200
142600361700
151100371700
161300384600
171100394700
181800404600
414500

c 60 ∙Tc

fFeed/rev mm/rev
kcMaterial specific cutting force N/mm2
hDistance from drill point to workpiece before feeding mm
LDepth of hole mm
CMhCost/machine hour $/h
ηMachine efficiency %
k90º}180° bottom drills
sin k1 DR...
k70º}140° point angle drills
sin k0.94
Drill Geometry Coeficient
DCM DCN SCD
km1 0.85 0.85
kf10.85 0.85